(1x+1)(x^2-1x+1)=

Solution for (1x+1)(x^2-1x+1)= equation:

Simplifying
(1x + 1)(x2 + -1x + 1) = 0

Reorder the terms:
(1 + 1x)(x2 + -1x + 1) = 0

Reorder the terms:
(1 + 1x)(1 + -1x + x2) = 0

Multiply (1 + 1x) * (1 + -1x + x2)
(1(1 + -1x + x2) + 1x * (1 + -1x + x2)) = 0
((1 * 1 + -1x * 1 + x2 * 1) + 1x * (1 + -1x + x2)) = 0
((1 + -1x + 1x2) + 1x * (1 + -1x + x2)) = 0
(1 + -1x + 1x2 + (1 * 1x + -1x * 1x + x2 * 1x)) = 0
(1 + -1x + 1x2 + (1x + -1x2 + 1x3)) = 0

Reorder the terms:
(1 + -1x + 1x + 1x2 + -1x2 + 1x3) = 0

Combine like terms: -1x + 1x = 0
(1 + 0 + 1x2 + -1x2 + 1x3) = 0
(1 + 1x2 + -1x2 + 1x3) = 0

Combine like terms: 1x2 + -1x2 = 0
(1 + 0 + 1x3) = 0
(1 + 1x3) = 0

Solving
1 + 1x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 1x3 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 1x3 = 0 + -1
1x3 = 0 + -1

Combine like terms: 0 + -1 = -1
1x3 = -1

Divide each side by '1'.
x3 = -1

Simplifying
x3 = -1

Reorder the terms:
1 + x3 = -1 + 1

Combine like terms: -1 + 1 = 0
1 + x3 = 0

The solution to this equation could not be determined.